CFAL STUDENTS EXCEL IN JEE MAIN (JANUARY) 2019
Samarth Bhat – NTA percentile score 99.9050835
Ankush Moger with NTA percentile Score 99.8790422
11 students scored above 99 percentile, 19 students above 98 percentile
Students who have scored more than 98 percentiles are as below.
|1||Samarth M Bhat||99.9050835|
|3||Chaithanya Shyam D||99.7415902|
|4||Shravan Singh Mehra||99.6614037|
|7||Vignesh R. Rao||99.3280302|
|8||K N Rajath Rao||99.3072956|
|11||Alina Melony Pinto||99.2586755|
|12||I. Vishnu Bharadwaj||98.9975167|
|15||Reeve Rocky Dsouza||98.6364928|
|19||Sharvani Laxmi Somayaji||98.1659437|
Details of Percentile and JEE Main 2019 ranking:
The first JEE (Main) Examination was conducted by National Testing Agency (NTA ) between 8th and12th January, 2019 in two shifts per day across 258 cities in the country and abroad. All the students had to answer through CBT (computer based test) mode.
Since this year the students had written the exam on different dates, the National testing Agency will rank the students based on the Percentile score. 9,29,198 students have registered for JEE Main 2019 (January), out of which 8,74,469 appeared for the exam.
NTA score is not the same as percentage of marks obtained.
Percentile score is based on the relative performance of all the students who appeared for the session. The topper of that session will get 100 % percentile.
The formula to calculate the percentile is = 100 × no. of students with marks< =the student total no. of stiudents who wrote the exam
After the JEE MAIN APRIL-2019 Exam , the Ranks of the candidates will be released taking into consideration better of the two NTA Scores of all candidates appeared in JAN 2019 and APRIL 2019 examinations and in accordance with the policy already made available on the website https://jeemain.nic.in.
The next online application for JEE (Main) April-2019 Examination shall start from 8th February and shall remain open till 7th March 2019. The uploading of images and payment of the application fee will be upto 8th March-2019. 16. The JEE (Main) April 2019 Examination will be conducted in CBT mode between 6th and 20th April, 2019.
How to calculate my JEE Main 2019 rank based on my NTA Percentile score?
Let’s take this for the January session of JEE Main 2019 first. As per the NTA declared result statistics, 8,74,469 students appeared for the exam across four days with two sessions each making that a total of eight sessions. There are 15 students who have scored 100 percentile in these sessions.
To calculate the JEE Main 2019 rank, you first need to know the percentage of people ahead of you with higher percentile scores. To calculate that, the formula would be 100 which is the highest score minus your percentile score.
Since the percentile is calculated from a scale ranging from 100 to 0 for each session of examinees, the formula applies the total number of students in the January session which is 874469 /100 multiplied by the percentage of people who are ahead of you to arrive at the rank.
Therefore, the formula to calculate the JEE Main 2019 rank for January 2019 is
JEE Main 2019 rank (probable) = (100- NTA percentile score ) X 874469 /100
If NTA percentile score is 90.70, JEE Main rank will be (100-90.70 ) X 874469/100 = 81325
Consider the NTA score of 80.60 then JEE Main 2019 rank = (100-80.60) X 874469 /100. The rank will be 169646.
** This formula would not be for a 100 percentile score as those are the top ranks
For more details contact:
Centre for advanced learning
Mob: 9845737120, 9740939374 or 7026238999
Present at the Press release:
Mrs.Severine Rosario (coordinator) CFAL
Mr.Vijay Moras (Coordinator) CFAL